PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00

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Physics Challenge Question 2: Displacement and velocity

Physics Challenge Question 2: Solutions


Question 1:

Time: 0.0 sec 1.0 sec 2.0 sec 3.0 sec 4.0 sec 5.0 sec 6.0 sec

PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00 PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00 PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00 PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00 PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00 PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00 PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00

Distance: 0.0 ft 5.0 ft 15 ft 25 ft 35 ft 55 ft 60 ft

PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00 PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00 PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00 PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00 PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00 PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00

5.0 ft/s

10 ft/s

10 ft/s

10 ft/s

20 ft/s

5.0 ft/s


Velocity:


Here, I just calculate the displacement and divide it by the time interval (each of those is 1 sec). For example, the second interval is, with 2 significant figures,

PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00


Question 2:

The average velocity is

PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00


Question 3:

I can use the first and last measurement to calculate the average velocity over the whole stretch. This is no coincidence – what happens in between doesn’t matter for the average velocity!

PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00


Question 4:

1 ft = 0.3048 m, so PHYSICS CHALLENGE QUESTION 2 SOLUTIONS QUESTION 1 TIME 00



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